我有以下字符串:
4563_1_some_data
总的模式是
r'\d{1,5}_[1-4]_some_data
Note, that numbers before first underscore may be the same for different some_data
So the question is: how to get all possible variants of replacement using regex?
Desired output:
[4563_1_some_data, 4563_2_some_data, 4563_3_some_data, 4563_4_some_data]
我的try 是:
[re.sub(r'_\d_', r'_[1-4]_', row).group() for row in data]
但它产生了结果:
4563_[1-4]_some_data
看起来像是普通的替代品.我应该如何激活图案更换并获得 list ？
您需要迭代Range对象来创建您的列表.
range对象:要做到这一点，您需要一个模式来从您的模式中获取[1-4]部分.import re
text = "4563_1_some_data"
original_pattern = r"\d{1,5}_[1-4]_some_data"
# A regex to get the `[1-4]` part.
find_numbers_pattern = r"(?<=_)\[(\d)\-(\d)\](?=_)"
# Get `1` and `4` to create a range object
a, b = map(int, re.search(find_numbers_pattern, original_pattern).groups())
# Use `count=` to only change the first match.
lst = [re.sub(r"(?<=_)\d(?=_)", str(i), text, count=1) for i in range(a, b + 1)]
print(lst)
输出:
['4563_1_some_data', '4563_2_some_data', '4563_3_some_data', '4563_4_some_data']
(?<=_)\[(\d)\-(\d)\](?=_) explanation:(?<=_):与_匹配的正向回溯断言.
\[(\d)\-(\d)\]:例如，为了获得[1-4].
(?=_):一个积极的前瞻断言，以找到_.