Python 将输入聚合到统一词典中

Nested_Dict =
{'candela_samples_generic': {'drc_dtcs': {'domain_name': 'TEMPLATE-DOMAIN', 'dtc_all':{ 
'0x930001': {'identification': {'udsDtcValue': '0x9300', 'FaultType': '0x11', 'description': 'GNSS antenna short to ground'}, 
'functional_conditions': {'failure_name': 'short_to_ground', 'mnemonic': 'DTC_GNSS_Antenna_Short_to_ground'}},
'0x212021': {'identification': {'udsDtcValue': '0x2120', 'FaultType': '0x21', 'description': 'ECU internal Failure'},
'functional_conditions': {'failure_name': 'short_to_ground', 'mnemonic': 'DTC_GNSS_Antenna_Short_to_ground'}}}}}}

Header = {
    'dtc_all': {
        'DiagnosticTroubleCodeUds': {'udsDtcValue': None, 'FaultType': None},
        'dtcProps': {'description': None},
        'DiagnosticTroubleCodeObd': {'failure_name': None}   
    }
}

SubkeyList = ['0x930001','0x240001']

从SubkeyList中取一个元素，从字典中取一个头键(可以有多个头键，比如dtc_all). 在头字典中迭代字典的值，例如'udsDtcValue'.

For example:
    Main_Key = dtc_all
    Sub_Key = 0x212021
    Element = udsDtcValue

将这些参数传递给函数get_value_nested_dict(nested_dict，Main_Key，Sub_Key，Element).这个函数将返回元素的值. get_value_nested_dict func，它与我发布的元素值检索预期一样工作. 同时，创建一个新字典，并在正确的位置更新元素值，例如'udsDtcValue':'0x9300 '. 此外，确保键的序列与标头中的相同. 类似地，在头字典内遍历字典的所有值，如FaultType、Description，直到failure_name. 对SubkeyList中的每个元素重复这些迭代，并以相同的顺序将结果附加到new_dict中. 有什么建议吗？

输出:New_Dict应该是这样的:

New_Dict= 
{'dtc_all': 
{'0x930001': {'DiagnosticTroubleCodeUds': {'udsDtcValue': '0x9300', 'FaultType': '0x11'}, 'dtcProps':{'description': 'GNSS antenna short to ground'}, 'DiagnosticTroubleCodeObd': {'failure_name':short_to_ground}}},
{'0x212021': {'DiagnosticTroubleCodeUds': {'udsDtcValue': '0x2120', 'FaultType': '0x21'}, 'dtcProps':{'description': 'ECU internal Failure'}, 'DiagnosticTroubleCodeObd': {'failure_name':short_to_ground}}}}

def get_value_nested_dict(nested_dict, main_key, sub_key, element):
    results = []
    def search_for_element(sub_dict, looking_for_element):
        if isinstance(sub_dict, dict):
            for k, v in sub_dict.items():
                if k == element and looking_for_element:
                    results.append(v)
                else:
                    search_for_element(v, looking_for_element)
    def search_nested_dict(current_dict):
        if isinstance(current_dict, dict):
            for key, value in current_dict.items():
                if key == main_key:
                    if sub_key in value:
                        search_for_element(value[sub_key], True)
                    else:
                        search_for_element(value, False)
                else:
                    search_nested_dict(value)
    search_nested_dict(nested_dict)
    return results