C++ 在Linux上使用vscode和lldb调试用Makefile编译的c代码

I am using vscode on archlinux and I need to debug line by line a C code compiled with a makefile.
I have create a task and a launch json which me allow to examine step by step, but I cannot inspect variable throw debug console or through vscode interface.

这是Makefile的摘录

CFLAGS  = -Wall -Wextra -Wextra -Wswitch-default -Wswitch-unreachable -Wswitch-bool \
          -Wmisleading-indentation -Wnull-dereference -Winit-self -Wstack-protector -Wformat \
          -Wformat-security -Wformat-overflow -Wdouble-promotion -Wunused-parameter -Wunused-const-variable \
          -Wuninitialized -Wpointer-arith -Wincompatible-pointer-types -Wbad-function-cast \
          -Wstrict-prototypes -Wmissing-prototypes -Wmissing-declarations -Wlong-long -Og -g -O0\
          -Ofast
LDFLAGS = -gdwarf-2 -L/usr/local/lib


.PHONY: clean cleandep mrproper

all: $(EXEC)

myprogram: $(OBJ)
    $(CC) -g  -o $@ $^ $(LDFLAGS) $(LIBS) 

[...]

debug: CFLAGS += -DDEBUG -g
debug: $(EXEC)

关于启动和任务json，它们与我在另一个文件中使用的相同(不使用Makefile进行编译)，所以我非常确定.

Basically, when I use the debug console "print <variable>", <variable> is not defined.
I copied this structure How to "fix" debugger in VScode if you have Makefile project on C++? but it used cppdb, which is not supported in archlinux.

更新 我的错误，在Main变量中打印，在Main调用的函数内部，我看不到变量内容(未声明的标识符)