C++ 无法将字符串文字分配给 C 中的字符数组

我正在try 将字符串字面赋值给字符array.

这段代码运行良好

#include <stdio.h>

struct student
{
    char* name;
};

struct student s[2];

void main()
{
    s[0].name = "jason";
    s[1] = s[0];

    printf("%s%s", s[0].name, s[1].name);

    s[1].name = "fedin";

    printf("%s%s", s[0].name, s[1].name);
}

但这段代码不起作用:

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

struct item {
  char* itemName;
  int quantity;
  float price;
  float amount;
};

void readItem(item* const p) {
  printf("Please enter item name. \n");
  fgets(p->itemName, 50, stdin);
  for (int i = 0; i < strlen(p->itemName); i++)
  {
    if (p->itemName[i] == '\n') {
      p->itemName[i] = NULL;
    }
  }

  printf("Please enter the quantity. \n");
  scanf_s("%d", &p->quantity);

  printf("Please enter the price. \n");
  scanf_s("%f", &p->price);
}

void print(item* const p) {
  printf("Item Name: %s \n", p->itemName);
  printf("Quantity: %i \n", p->quantity);
  printf("Price: %.4f \n", p->price);

  p->amount = (p->quantity) * (p->price);
  printf("Amount: %.4f \n", p->amount);
}

int main(void) {
  struct item item1;

  item1.itemName = "SDfsd";

  item1.quantity = 0;
  item1.price = 0.0;
  item1.amount = 0.0;

  struct item* itemP = &item1;

  readItem(itemP);
  print(itemP);

  free(itemP->itemName);
  itemP->itemName = NULL;

  return 0;

}

编译器给我的错误:

Error (active)  E0513 a value of type "const char *" cannot be assigned to an entity of type "char *" Structure Pointers and Functions  F:\Mohamed Taha\Codes\C Programming\C Programming For Beginners\vs\Structure Pointers and Functions\Structure Pointers and Functions\mian.cpp 41  

像往常一样，我试着先问ChatGPT，但它没有给我任何解释.它说错误是因为字符串文字在只读内存中，所以您不能写入它们，但这没有任何意义，因为第一个代码可以工作.

注意:这两段代码在同一个编译器上运行.