C++ 计算 e^x 很好.但不是 x 的罪

我对编程还很陌生.我知道这段代码看起来也不是很好的设计.如果我不应该问这样的问题，请让我知道.我会把它记下来，然后自己解决问题(希望如此).

我的第一个使用泰勒级数计算e^x的程序运行良好:

#include <stdio.h>
#include <math.h>

double calculateTaylorSeries(double x, int n) {
    double result = 1.0; // The first term in the series

    double term = 1.0;
    for (int i = 1; i <= n; i++) {
        term *= x / i; 
        result += term; 
    }

    return result;
}

int main(void) {
    double x;

    printf("Enter the value of x: ");
    scanf("%lf", &x);

    int n;
    printf("Enter the number of terms (n): ");
    scanf("%d", &n);

    double taylorApproximation = calculateTaylorSeries(x, n);

    printf("e^%.2lf (approximated using %d terms): %lf\n", x, n, taylorApproximation);

    return 0;
}

但对sin函数做同样的事情似乎很困难.因为有一个交替的术语方面.而权力和分母必须是奇数.

我的逻辑在我看来是正确的.但它给了我不准确的结果.

#include <stdio.h>
#include <math.h>

double calculateTaylorSeries(double x, int n)
{
    double result = x;
    double term = 1.0;
    int sign = -1;
    for (int i = 1; i <= 2 * n; i++)
    {
        if (i % 2 == 1)
        {
            term *= x / i * sign; //term = term * x/i * sign;

            result += term; // result = result + term;
        }
    }

    return result; 
}

int main(void)
{
    double x; 
    printf(" Enter the angle : ");

    scanf("%lf", &x);
    
    int n;
    
    printf("Enter the number of terms(n):");
    scanf("%d", &n);

    double sinX = calculateTaylorSeries(x, n);

    printf("sin(%lf) = %lf", x, sinX);

    return 0;
}

以下是输出:

Enter the angle : 6.28
Enter the number of terms(n):2
sin(6.280000) = 13.146133

Enter the angle : 234
Enter the number of terms(n):15 
sin(234.000000) = -49592774856964366336.000000

我还搞不懂为什么在VS代码中运行这段代码时，它会显示以下错误:

The preLaunchTask 'C/C++:gcc.exe build active file' terminated with exit code -1.