Rust 使用在功能标志后面导入的类型，即使未启用功能标志

这是我的Cargo .

[package]
name = "tmp"
version = "0.1.0"
edition = "2021"

[dependencies]
chrono = "0.4.24"
chrono-tz = {version="0.8.2", optional = true}

[features]
my_feature = ["chrono-tz"]

以下是我的src/main.rs条建议:

#[cfg(feature = "some_feature")]
use chrono_tz::Tz;

#[cfg(feature = "some_feature")]
fn my_fn(tz: Tz){
    println!("tz is: {:?}", tz);
}


fn feature_function(tz: Option<Tz>) {
    match tz {
        #[cfg(feature = "some_feature")]
        Some(tz) => my_fn(tz),
        _ => (),
    }
}

fn main() {
    feature_function(None);
}

注意feature_function是如何接受tz: Optional<Tz>的，但是只有在启用了"SOME_FEATURE"时才会达到Some(tz)的情况.

因此，如果我没有启用"SOME_FEATURE"，我希望能够用tz=None呼叫feature_function.

可以预见的是，这不会编译:

error[E0412]: cannot find type `Tz` in this scope
  --> src/main.rs:10:32
   |
10 | fn feature_function(tz: Option<Tz>) {
   |                                ^^ not found in this scope
   |
help: you might be missing a type parameter
   |
10 | fn feature_function<Tz>(tz: Option<Tz>) {
   |                    ++++

For more information about this error, try `rustc --explain E0412`.
error: could not compile `tmp` due to previous error

有没有什么技巧可以用来在feature_function中输入tz，这样如果没有启用"SOME_FEATURE"，我仍然可以用tz=None呼叫feature_function？