Rust 返回引用字符串的future

我正在try 创建一个Futures中的Vec，以便与try_join_all一起使用.

use futures::future::try_join_all;

struct Image {
    pub file_name: String,
}

struct Storage;

impl Storage {
    async fn upload(&self, filename: &str) -> Result<String, ()> {
        Ok(filename.to_owned())
    }
}

struct ImagesRepository {
    storage: Storage,
}

impl ImagesRepository {
    async fn upload_images(&self, images: &[Image]) -> Result<Vec<String>, ()> {
        let futures = images
            .iter()
            .map(|image| {
                let path_name = format!("somedirectory/{}", &image.file_name);

                let future = self.storage.upload(path_name.as_str());

                future
            })
            .collect::<Vec<_>>();

        let results = try_join_all(futures).await?;

        Ok(results)
    }
}

但是，我收到以下编译器错误:

   Compiling playground v0.0.1 (/playground)
error[E0515]: cannot return value referencing local variable `path_name`
  --> src/lib.rs:30:17
   |
26 |                 let future = self.storage.upload(path_name.as_str());
   |                                                  ------------------ `path_name` is borrowed here
...
30 |                 future
   |                 ^^^^^^ returns a value referencing data owned by the current function

For more information about this error, try `rustc --explain E0515`.
error: could not compile `playground` due to previous error

这是因为我向storage.upload传递了一个对path_name的引用，它只存在于闭包中.

我知道我可以将storage.upload改为String，但这意味着要破解使用此函数的其他部分的代码.

有没有办法修复这个编译器错误？

Minimal example - Rust Playground个