Python 迭代嵌套字典的值

Nested_Dict =
    {'candela_samples_generic': {'drc_dtcs': {'domain_name': 'TEMPLATE-DOMAIN', 'dtc_all':{ 
    '0x930001': {'identification': {'udsDtcValue': '0x9300', 'FaultType': '0x11', 'description': 'GNSS antenna short to ground'}, 
    'functional_conditions': {'failure_name': 'short_to_ground', 'mnemonic': 'DTC_GNSS_Antenna_Short_to_ground'}},
    '0x212021': {'identification': {'udsDtcValue': '0x2120', 'FaultType': '0x21', 'description': 'ECU internal Failure'},
    'functional_conditions': {'failure_name': 'short_to_ground', 'mnemonic': 'DTC_GNSS_Antenna_Short_to_ground'}}}}}}
   
 Header = {
        'dtc_all': {
            'DiagnosticTroubleCodeUds': {'udsDtcValue': None, 'FaultType': None},
            'dtcProps': {'description': None},
            'DiagnosticTroubleCodeObd': {'failure_name': None}   
        }
    }
    
SubkeyList = ['0x930001','0x212021']

Expected Output:    
New_Dict= 
{'dtc_all': 
{'0x930001': {'DiagnosticTroubleCodeUds': {'udsDtcValue': '0x9300', 'FaultType': '0x11'}, 'dtcProps':{'description': 'GNSS antenna short to ground'}, 'DiagnosticTroubleCodeObd': {'failure_name':short_to_ground}}},
{'0x212021': {'DiagnosticTroubleCodeUds': {'udsDtcValue': '0x2120', 'FaultType': '0x21'}, 'dtcProps':{'description': 'ECU internal Failure'}, 'DiagnosticTroubleCodeObd': {'failure_name':short_to_ground}}}}

参考问题:Aggregating Inputs into a Consolidated Dictionary

这里想在头字典内迭代头字典的值，但用我的代码，它迭代的是dict的键，而不是dict的值. 从SubkeyList中取一个元素，从字典中取一个头键(可以有多个头键，比如dtc_all).在头字典中迭代字典的值，例如'udsDtcValue'.

For example:
  Main_Key = dtc_all
  Sub_Key = 0x212021
  Element = udsDtcValue

将这些参数传递给函数get_value_nested_dict(nested_dict，Main_Key，Sub_Key，Element).这个函数将返回元素的值.get_value_nested_dict func，它与我发布的元素值检索预期一样工作.同时，创建一个新字典，并在正确的位置更新元素值，例如'udsDtcValue':'0x9300 '.此外，确保键的序列与标头中的相同.类似地，在头字典内遍历字典的所有值，如FaultType、Description，直到failure_name.对SubkeyList中的每个元素重复这些迭代，并以相同的顺序将结果附加到new_dict中.有什么建议吗？

def create_new_dict(Nested_Dict, Header, SubkeyList):
    new_dict = {}
    for sub_key in SubkeyList:
        sub_dict = {}
        for element, value in Header['dtc_all'].items():
            value = get_value_nested_dict(Nested_Dict, 'dtc_all', sub_key, element)
            if value:
                sub_dict[element] = value[0]
        new_dict[sub_key] = sub_dict
    return new_dict