Python 如何获取包含`try`外部堆栈的`__traceback__`属性的异常

在Python(3.10)中，一个异常在try中引发，包含一个不会扩展到try的调用位置的回溯. 这对我来说有点令人惊讶，更重要的是，这不是我想要的.

这里有一个简短的程序来说明这个问题:

# short_tb.py
import traceback


def caller():
    somefunction()


def somefunction():
    try:
        raise ValueError("This is a value error")
    except ValueError as e:
        # in my actual code, e is passed to a function, and __traceback__ is pulled from it for logging at this other
        # location; the code below simply demonstrates the lack of frames in the traceback object
        print("".join(traceback.format_tb(e.__traceback__)))


print("This will produce a traceback with only one frame, the one in somefunction()")
caller()


def caller2():
    somefunction2()


def somefunction2():
    raise ValueError("This is a value error")


print("This will produce a traceback with all relevant frames (the default behavior of the python interpreter)")
caller2()

输出:

This will produce a traceback with only one frame, the one in somefunction()
  File ".../short_tb.py", line 10, in somefunction
    raise ValueError("This is a value error")

This will produce a traceback with all relevant frames (the default behavior of the python interpreter)
Traceback (most recent call last):
  File ".../short_tb.py", line 30, in <module>
    caller2()
  File ".../short_tb.py", line 22, in caller2
    somefunction2()
  File ".../short_tb.py", line 26, in somefunction2
    raise ValueError("This is a value error")
ValueError: This is a value error

我希望__traceback__包含第二个例子中的所有信息.我很高兴覆盖变量，我可以在异常处理位置这样做.但是我如何才能得到一个对象来实现这个目的呢？

在这个问题中，有很多关于追溯的答案，但似乎没有一个是关于traceback objects的: Catch and print full Python exception traceback without halting/exiting the program个