为什么我只看到一个字母而不是"cube" 当我没有输入dtype="str"时，它起作用了. 我的问题是为什么？
代码:
np.full((3,3,3),"cube",dtype=str)
结果:
array([[['c', 'c', 'c'],
['c', 'c', 'c'],
['c', 'c', 'c']],
[['c', 'c', 'c'],
['c', 'c', 'c'],
['c', 'c', 'c']],
[['c', 'c', 'c'],
['c', 'c', 'c'],
['c', 'c', 'c']]], dtype='<U1')
np.full((3,3,3),"cube",dtype=str)
is equivalent to个
np.full((3,3,3),"cube",dtype='U1')
它将只接受字符串的第一个元素.
您可以通过以下方式获得完整的结果:
np.full((3,3,3),"cube",dtype=object)
或
np.full((3,3,3),"cube",dtype='U4') # U4 as you have 4 letters in cube, you can do any U>4 like U5, U6, etc.
或 just remove dtype=str. Upon removing it will take the complete length of the string.
np.full((3,3,3),"cube")