Python 如果实体重复，如何绘制断条

不确定您到底想要什么，但您可以手动绘制条形图:

import matplotlib.pyplot as plt
import matplotlib.patches as mpatches

ys = {k: i for i, k in enumerate(result['Person'].unique())}

ax = plt.subplot()

height = 0.5

for row in result.itertuples():
    y = ys[row.Person]
    x0 = row.Year_start
    x1 = row.Year_left
    #                         bottom left corner  width    height
    rect = mpatches.Rectangle((x0, y - height/2), x1 - x0, height,
                              facecolor='grey')
    ax.add_patch(rect)

ax.set_ylim(0-height, len(ys)-1+height)
ax.set_xlim(result['Year_start'].min()-1, result['Year_left'].max()+1)
ax.set_yticks(range(len(ys)), list(ys))

NB. Danny has overlapping dates, which are thus overlapping. If this is not expected, please clarify.个

输出:

using broken_barh:

ax = plt.subplot()

height = 0.5
for y, (name, g) in enumerate(result.groupby('Person')):
    ax.broken_barh(list(zip(g['Year_start'],
                            g['Year_left']-g['Year_start'])),
                   (y-height/2, height)
                   )
names = sorted(result['Person'].unique())
ax.set_ylim(0-height, len(names)-1+height)
ax.set_xlim(result['Year_start'].min()-1, result['Year_left'].max()+1)
ax.set_yticks(range(len(names)), names)