Selenium 无法使用 xpath 或 ClassName 或 Css Select 器 (Python) 找到元素

您好，我正在try 点击Google Look上的不谢谢按钮:enter image description here

该按钮的完整元素如下所示

<button aria-label="No thanks" class="M6CB1c rr4y5c" jsname="ZUkOIc" jslog="71121; track:click;" data-dismiss="n">No thanks</button>

我try 使用XPath Select 它，如下所示 编辑:我在代码中添加了一个等待元素Wait = WebDriverWait(driver,60)

driver.get("https://www.google.com/")

Wait = WebDriverWait(driver,60)

buttonSignIn = "//button[@class='M6CB1c rr4y5c'][1]/@class"

Wait.until(EC.visibility_of_any_elements_located((By.XPATH,buttonSignIn)))

buttonSign = driver.find_elements(By.XPATH,buttonSignIn)

print(buttonSign.get_attribute("innerHTML"))

我之前也try 过用这样的css来 Select 它

buttonSignIn = ".M6CB1c.rr4y5c"

Wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR,buttonSignIn)))

buttonSign = driver.find_element(By.CSS_SELECTOR,buttonSignIn)

print(buttonSign.get_attribute("innerHTML"))

我还try 使用如下所示的类名 Select 它

buttonSignIn = "M6CB1c rr4y5c"

Wait.until(EC.visibility_of_element_located((By.CLASS_NAME,buttonSignIn)))

buttonSign = driver.find_element(By.CLASS_NAME,buttonSignIn)

print(buttonSign.get_attribute("innerHTML"))

我跟踪了堆栈溢出中出现问题的其他内容.我做错了什么？