Python NameError：名称移动未定义

发布于09月09日

class mobile:
    def __init__(self,brandname,color,isjack):

        self.brand=brandname
        self.color=color
        self.isjack=isjack

    def calling(self):
        print('calling')

    def cameraclick(self):
        print('picture is clicked')

    def message(self):
        print('message_sent')

    def main():

        m1=mobile('apple','black',False)
        print(m1.brand)
        print(m1.color)
        print(m1.isjack)
        m1.calling()
        m1.cameraclick()
        m1.message()   

        print("-------------------")

        m2=mobile('samsung','grey',False)
        print(m2.brand)
        print(m2.color)    
        print(m2.isjack)
        
    if __name__=='__main__':
        main()

我编写了一个基本代码来判断为什么我得到的名称是错误的.有没有人能帮忙？

推荐答案

你过得怎么样？

这是发生BCS上的缩进错误的代码！

Python uses indentation to indicate a block of code.个

如果main位于class mobile块内，则只有在调用它时在其前面加上关键字mobile才能被调用

因此，您需要取消对def main():和if __name__ == '__main__':方法的缩进，并将其缩进到根级别.

class Mobile:
    def __init__(self, brandname, color,isjack):
        self.brand=brandname
        self.color=color
        self.isjack=isjack

    def calling(self):
        print('calling')

    def cameraclick(self):
        print('picture is clicked')

    def message(self):
        print('message_sent')

def main():
    m1 = Mobile("apple", "black", False)
    print(m1.brand)
    print(m1.color)
    print(m1.isjack)
    m1.calling()
    m1.cameraclick()
    m1.message()

    print("-------------------")

    m2 = Mobile("samsung", "grey", False)
    print(m2.brand)
    print(m2.color)
    print(m2.isjack)

if __name__=='__main__':
    main()

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