Python3.x 过滤并获取数据框中条件之间的行

我的DataFrame如下所示:

+----------------------------------+---------+
|               Col1               |  Col2   |
+----------------------------------+---------+
| Start A                          |    1    |
| value 1                          |    2    |
| value 2                          |    3    |
| value 3                          |    4    |
| value 5                          |    5    |
| End A                            |    6    |
| value 6                          |    3    |
| value 7                          |    4    |
| value 8                          |    5    |
| Start B                          |    1    |
| value 1                          |    2    |
| value 2                          |    3    |
| value 3                          |    4    |
| value 5                          |    5    |
| End B                            |    6    |
| value 6                          |    3    |
| value 7                          |    4    |
| value 8                          |    5    |
| Start C                          |    1    |
| value 1                          |    2    |
| value 2                          |    3    |
| value 3                          |    4    |
| value 5                          |    5    |
| End C                            |    6    |
+----------------------------------+---------+

我试图获得的是，如果出现子串Start和End，我想要它们之间的行. 预期结果为:

+----------------------------------+---------+
|               Col1               |  Col2   |
+----------------------------------+---------+
| Start A                          |    1    |
| value 1                          |    2    |
| value 2                          |    3    |
| value 3                          |    4    |
| value 5                          |    5    |
| End A                            |    6    |
| Start B                          |    1    |
| value 1                          |    2    |
| value 2                          |    3    |
| value 3                          |    4    |
| value 5                          |    5    |
| End B                            |    6    |
| Start C                          |    1    |
| value 1                          |    2    |
| value 2                          |    3    |
| value 3                          |    4    |
| value 5                          |    5    |
| End C                            |    6    |
+----------------------------------+---------+

我试了一下这个How to filter dataframe columns between two rows that contain specific string in column?的代码

m = df['To'].isin(['Start A', 'End A']).cumsum().eq(1)
df[m|m.shift()]

但这只返回第一组开始和结束，它也需要准确的字符串.

输出:

+----------------------------------+---------+
|               Col1               |  Col2   |
+----------------------------------+---------+
| Start A                          |    1    |
| value 1                          |    2    |
| value 2                          |    3    |
| value 3                          |    4    |
| value 5                          |    5    |
| End A                            |    6    |
+----------------------------------+---------+