我想在输入值中显示旧的输入.如果没有旧输入,则显示其他变量:
value="{{ old('salary_' . $employee->id) or 'Default' }}"
But when there is no old input, it gives me 1 instead of the default value!
I think the problem has something to do with the concatenation, but I don't know how to fix it!?