有关如何解决使用 JavaScript 从字符串中仅提取数字的问题的建议

function extractNumbers(str) {
  //Use replace() to replace all instances of letters/alpha*

  let onlyNumbersString = str.replace(/[a-z]/ig, '');

  //remove "," using replace()*

  onlyNumbersString = onlyNumbersString.replace(",", "");

  //Create an array of numbers* 
  let arrayOfNumbers = onlyNumbersString.split(',');


  let result = arrayOfNumbers.map((x) => parseFloat(x))
  console.log(arrayOfNumbers)
  console.log(result);

  const filtered = result.filter(function(e) {
    return e
  })
  console.log(filtered)
}


let numbers = "12.3,Name1,3,4,Name2,35,Name3" //returns [12.3,3,4,35]
//"12.3,22,Q" returns [12.322]*

extractNumbers(numbers)

onlyNumbersString = onlyNumbersString.replace(",", "");

function extractNumbers(str) {
    // Split on commas, since that seems to be the delimiter you want
    const parts = str.split(",");

    // Remove any strings that aren't all number chars (including `.`)
    const filtered = parts.filter((s) => !/[^.\d]/.test(s));

    // Convert to number
    const numbers = filtered.map((s) => parseFloat(s));
    return numbers;
}

console.log(extractNumbers("12.3,Name1,3,4,Name2,35,Name3"));

function extractNumbers(str) {
    const parts = str.split(",");
    const filtered = parts.filter((s) => !/[^.\d]/.test(s));
    const numbers = filtered.map((s) => parseFloat(s));
    return numbers;
}

function extractNumbers(str) {
    return str
        .split(",")
        .filter((s) => !/[^.\d]/.test(s))
        .map((s) => parseFloat(s));
}

function extractNumbers(str) {
    const parts = str.split(",");
    const numbers = parts.map((s) => s.trim() ? +s : NaN);
    const validNumbers = numbers.filter((num) => !isNaN(num));
    return validNumbers;
}

console.log(extractNumbers("12.3,Name1,3,4,Name2,35,Name3"));

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