Go time.Parse 无效的 ISO 日期

发布于06月10日

Is there a way to parse the following date string using time.Parse:
2023-06-06T07:04:58:278-07?

我try 使用格式2006-01-02T15:04:05:000Z07，但最后的:导致错误.

推荐答案

编写一个time.Parse包装函数以接受小数点、小数点逗号或冒号作为秒小数分隔符.

package main

import (
    "fmt"
    "strings"
    "time"
)

// Accept a decimal point, decimal comma, or colon
// as the seconds decimal separator.
func timeParse(layout, value string) (time.Time, error) {
    t, err := time.Parse(layout, value)
    if err == nil {
        return t, err
    }
    if strings.Count(value, ":") != 3 {
        return t, err
    }
    i := strings.LastIndexByte(value, ':')
    if i < 0 {
        return t, err
    }
    value2 := value[:i] + "." + value[i+1:]
    t2, err2 := time.Parse(layout, value2)
    if err2 == nil {
        return t2, err2
    }
    return t, err
}

func main() {
    inDate := "2023-06-06T07:04:58:278-07"
    parseFormat := "2006-01-02T15:04:05Z07"
    t, e := timeParse(parseFormat, inDate)
    if e != nil {
        fmt.Println(e)
    }
    fmt.Println(t)
}

https://go.dev/play/p/bjk8sw5yL78个