Go 泛型：实现嵌套接口

我正在try 使用泛型来实现接口Interface.它有一个接受另一个接口作为参数的方法:

type SubInterface interface {
    SendResponse(string)
}

type Interface interface {
    Subscribe(SubInterface)
}

我想出了这些接口的以下通用版本:

type GenericSubInterface[T any] interface {
    SendResponse(T)
}

type GenericInterface[Res any] interface {
    Subscribe(GenericSubInterface[Res])
}

我希望GenericInterface[string]可以赋值给Interface，但不知何故并不是这样.

var a Interface
var b GenericInterface[string]

//  cannot use b (variable of type GenericInterface[string]) as Interface value in assignment: GenericInterface[string] does not implement Interface (wrong type for method Subscribe)
//      have Subscribe(GenericSubInterface[string])
//      want Subscribe(SubInterface)
a = b

创建Interface的通用实现也不起作用:

type GenericImplementation[Res any] struct {
}

func (i *GenericImplementation[Res])Subscribe(ss GenericSubInterface[Res]) {
    var msg Res
    ss.SendResponse(msg)
}

//  cannot use &GenericImplementation[string]{} (value of type *GenericImplementation[string]) as Interface value in variable declaration: *GenericImplementation[string] does not implement Interface (wrong type for method Subscribe)
//      have Subscribe(GenericSubInterface[string])
//      want Subscribe(SubInterface)
var c Interface = &GenericImplementation[string]{}

在我看来奇怪的是，子接口可以相互分配:

var d SubInterface
var e GenericSubInterface[string]

// works fine
d = e

这个问题似乎只有在接口以某种方式嵌套时才会发生.有没有办法解决这个问题，我可以使用string以外的类型的泛型来实现Interface？

Full playground example个