With strings.Replacer
使用strings.Replacer
,实现你的愿望的格式化程序是非常简单和紧凑的.
func main() {
file, err := "/data/test.txt", "file not found"
log("File {file} had error {error}", "{file}", file, "{error}", err)
}
func log(format string, args ...string) {
r := strings.NewReplacer(args...)
fmt.Println(r.Replace(format))
}
输出(在Go Playground上试用):
File /data/test.txt had error file not found
我们可以通过自动将括号添加到log()
函数中的参数名称来使其使用起来更舒适:
func main() {
file, err := "/data/test.txt", "file not found"
log2("File {file} had error {error}", "file", file, "error", err)
}
func log2(format string, args ...string) {
for i, v := range args {
if i%2 == 0 {
args[i] = "{" + v + "}"
}
}
r := strings.NewReplacer(args...)
fmt.Println(r.Replace(format))
}
输出(在Go Playground上试用):
File /data/test.txt had error file not found
是的,您可以说这只接受string
个参数值.这是真的.稍有改进,这就不是真的了:
func main() {
file, err := "/data/test.txt", 666
log3("File {file} had error {error}", "file", file, "error", err)
}
func log3(format string, args ...interface{}) {
args2 := make([]string, len(args))
for i, v := range args {
if i%2 == 0 {
args2[i] = fmt.Sprintf("{%v}", v)
} else {
args2[i] = fmt.Sprint(v)
}
}
r := strings.NewReplacer(args2...)
fmt.Println(r.Replace(format))
}
输出(在Go Playground上试用):
File /data/test.txt had error 666
它的一个变体接受params作为map[string]interface{}
,并将结果返回为string
:
type P map[string]interface{}
func main() {
file, err := "/data/test.txt", 666
s := log33("File {file} had error {error}", P{"file": file, "error": err})
fmt.Println(s)
}
func log33(format string, p P) string {
args, i := make([]string, len(p)*2), 0
for k, v := range p {
args[i] = "{" + k + "}"
args[i+1] = fmt.Sprint(v)
i += 2
}
return strings.NewReplacer(args...).Replace(format)
}
试试Go Playground码.
With text/template
您的模板解决方案或提案也太过冗长.它可以像这样紧凑地编写(省略错误判断):
type P map[string]interface{}
func main() {
file, err := "/data/test.txt", 666
log4("File {{.file}} has error {{.error}}", P{"file": file, "error": err})
}
func log4(format string, p P) {
t := template.Must(template.New("").Parse(format))
t.Execute(os.Stdout, p)
}
输出(在Go Playground上try ):
File /data/test.txt has error 666
如果您想返回string
(而不是将其打印到标准输出),您可以这样做(在Go Playground上试用):
func log5(format string, p P) string {
b := &bytes.Buffer{}
template.Must(template.New("").Parse(format)).Execute(b, p)
return b.String()
}
使用显式参数索引
另一个答案中已经提到了这一点,但为了完成这一点,要知道相同的显式参数索引可以被任意次数使用,从而导致相同的参数被多次替换.阅读更多关于这个问题的信息:Replace all variables in Sprintf with same variable