C++ 如何使用_newindex数组我总是得到错误的参数

我正在编写C代码来判断和修改lua中的 struct 成员，我使用元表

它适用于简单的定义，但在数组中我不能使其工作，我有以下代码

struct pinfo {
    int time;
    bool hide_name;
    int type_info[10];
};

struct mystruct {
    int id;
    int value;
    int option[20];
    struct pinfo pf[5];
    ....
};


int Get_mystruct(lua_State *L) {
    struct mystruct *ms = (struct mystruct*)lua_touserdata(L, 1);

    lua_pushlightuserdata(L, ms);
    luaL_getmetatable(L, "mystruct");
    lua_setmetatable(L, -2);

    return 1;
}

int mystruct_index(lua_State *L) {
    struct mystruct *ms = (struct mystruct*)lua_touserdata(L, 1);
    const char *field = lua_tostring(L, 2);


    if (strcmp(field, "id") == 0) {
        lua_pushinteger(L, ms->id);
    }
    else if (strcmp(field, "value") == 0) {
        lua_pushinteger(L, ms->value);
    }
    else if (strcmp(field, "option") == 0) {
        lua_pushinteger(L, ms->option[lua_tointeger(L, 3)]);
    }
    else {
        lua_pushnil(L);
    }

    return 1;
}
    
int mystruct_newindex(lua_State  *L) {
    struct mystruct *ms = (struct mystruct*)lua_touserdata(L, 1);
    const char *field = lua_tostring(L, 2);
    int value = (int)lua_tointeger(L, 3);


    if (strcmp(field, "id") == 0) {
        ms->id = value;
    }
    else if (strcmp(field, "value") == 0) {
        ms->value = value;
    }
    else if (strcmp(field, "option") == 0) {
        ms->option[lua_tointeger(L, 3)] = (int)lua_tointeger(L, 4);
    } else {
        lua_pushnil(L);
    }

    return 0;
}

void mystruct_create(lua_State *L) {
    luaL_Reg mystructData[] = {
        { "GetMyStruct", Get_mystruct},
        { "__index", mystruct_index},
        { "__newindex", mystruct_newindex},
        {NULL, NULL}
    };

    luaL_newmetatable(L, "mystruct");
    luaL_setfuncs(L, mystructData, 0);
    lua_setfield(L, -2, "MyStructLua");
}

在Lua中，我的用法如下

local ms = MyStructLua.GetMyStruct(my_ptr)

print(ms.id) // Returns 0, not defined
ms.id = 1000 
print(ms.id) // Returns 1000, has been defined

现在，当我go 定义数组时，例如，当我try 时出现问题

for o = 0, 19 do
    mp.option[o] = 1
end

当我设置该值时，出现错误bad argument #3 to 'index' (number expected, got no value)

我想知道如何在这个元表中使用简单和复杂的数组，我有struct，它是mystruct的成员数组，我如何将它添加到_newindex和_index中