C++ 在列表中插入Int指针(C)

我是个新手，需要一些大学作业(job)代码的帮助. 我正在try 用C语言编写将 node 插入到列表末尾的代码，但创建新 node 的操作不起作用.

首先，这是我在作业(job)中收到的代码:

typedef struct listNode {
    int* dataPtr;
    struct listNode* next;
}ListNode;

typedef struct list
{
    ListNode* head;
    ListNode* tail;
}List;

并且:

List getList()
{
    List res;
    int size, num, i;
    makeEmptyList(&res);
    printf("Please enter the number of items to be entered:\n");
    scanf("%d", &size);
    printf("Please enter the numbers:\n");
    for(i = 0; i < size; i++)
    {
        scanf("%d", &num);
        insertDataToEndList(&res, num);
    }
    return res;
}

void main()
{
    List lst1, lst2, mergedList;
    lst1 = getList();
    lst2 = getList();
    mergedList = merge(lst1,lst2);
    printf("Merged list:\n");
    printList(&mergedList);

    freeList(&lst1);
    freeList(&lst2);
    freeList(&mergedList);
}

下面是我try 编写的insertDataToEndList个代码:

// Add Node to end list

void insertDataToEndList(List* lst, int data)
{
    ListNode* newTail;
    newTail = createNewListNode(&data, NULL);
    insertNodeToEndList(lst, newTail);
}
ListNode* createNewListNode(int* data, ListNode* next)
{
    ListNode* res;
    res = (ListNode*)malloc(sizeof(ListNode));
    res->dataPtr = data;
    res->next = next;
    return res;
}

void insertNodeToEndList(List* lst, ListNode* tail)
{
    if (isEmptyList(lst) == true)
        lst->head = lst->tail = tail;
    else
    {
        lst->tail->next = tail;
        lst->tail = tail;
    }
    tail->next = NULL;
}

问题是，当我打印已经输入的两个列表时，打印值根本不是我输入的值.