C和C++中字符的大小是多少？据我所知，字符的大小在C和C++中都是1字节.
100
#include <stdio.h>
int main()
{
printf("Size of char : %d\n", sizeof(char));
return 0;
}
100
#include <iostream>
int main()
{
std::cout << "Size of char : " << sizeof(char) << "\n";
return 0;
}
不出意外，它们都给出了输出:Size of char : 1
现在我们知道字符被表示为'a''b''c''|'，...所以我只是修改了上面的代码:
In C:个
#include <stdio.h>
int main()
{
char a = 'a';
printf("Size of char : %d\n", sizeof(a));
printf("Size of char : %d\n", sizeof('a'));
return 0;
}
100
Size of char : 1
Size of char : 4
In C++:
#include <iostream>
int main()
{
char a = 'a';
std::cout << "Size of char : " << sizeof(a) << "\n";
std::cout << "Size of char : " << sizeof('a') << "\n";
return 0;
}
100
Size of char : 1
Size of char : 1
Why the 100 returns different values in C and C++?