Swift 如何为任务扩展的泛型静态函数获得自动类型推理

我编写这个扩展是为了在等待多个异步任务并行时简化代码.

extension Task{
    static func race<T>(_ tasks:[() async throws -> T]) async throws -> T
    {
        return try await withThrowingTaskGroup(of: T.self) { taskGroup in
            for task in tasks {
                taskGroup.addTask(operation: task)
            }
            let first = try await taskGroup.next()
            taskGroup.cancelAll()
            return first!
        }
    }
    
    static func all<T>(_ tasks:[() async throws -> T]) async throws -> [T]
    {
        return try await withThrowingTaskGroup(of: T.self) { taskGroup in
            for task in tasks {
                taskGroup.addTask(operation: task)
            }
            return try await taskGroup.collectAsArray()
        }
    }
}

extension AsyncSequence{
    func collectAsArray() async rethrows -> [Element]
    {
        var results: [Element] = []
        for try await result in self
        {
            results.append(result)
        }
        return results
    }
}

但我得到Generic parameter 'Failure' could not be inferred和Generic parameter 'Success' could not be inferred错误时，使用它们

let x = try await Task.race([{return 1},{return 2}])
let y = try await Task.all([{return 1},{return 2}])

因此，我必须通过显式指定返回类型来消除错误

let x = try await Task<Int,Error>.race([{return 1},{return 2}])
let y = try await Task<Int,Error>.all([{return 1},{return 2}])

有没有可能让它自动推断返回类型和错误类型，这样我就不需要显式地编写它们？