Rust 如何将实现多个特征的 struct 传递给接受这些特征为&；mut

我正在处理一个可以简化为以下代码的问题.结果是error[E0499]: cannot borrow *Dog as mutable more than once at a time..

我很清楚这个错误的根源，但我想知道解决它的正确方法是什么？ 请注意，Walker和Swimmer特征使用一个公共字段来减少剩余的energy个特征，所以对我来说，让Dog同时实现这两个特征是有意义的.

我想保持功能move_around不变，因为行走和游泳的顺序对我很重要:)任何帮助都将不胜感激.

trait Swimmer {
    fn swim(&mut self);
}

trait Walker {
    fn walk(&mut self);
}

struct Fish {}

impl Swimmer for Fish {
    fn swim(&mut self) {}
}

struct Turtle {}

impl Walker for Turtle {
    fn walk(&mut self) {}
}

struct Dog {
    energy: usize,
}

impl Swimmer for Dog {
    fn swim(&mut self) {
        self.energy -= 1;
    }
}

impl Walker for Dog {
    fn walk(&mut self) {
        self.energy -= 1;
    }
}

fn move_around(walker: &mut dyn Walker, swimmer: &mut dyn Swimmer) {
    walker.walk();
    swimmer.swim();
}

fn main() {
    // This does not compile: error[E0499]: cannot borrow `*dog` as mutable more than once at a time
    let dog = &mut Dog { energy: 100 };
    move_around(dog, dog);

    // Works fine.
    // move_around(&mut Turtle {}, &mut Fish {});
}

我找到的一种可能的解决方案是拆分borrow -这意味着向Dog struct 添加Walker和Swimmer个字段并将它们传递给函数，但共享状态使其变得复杂.

Edit个

我猜在本例中，我可以使用我想要避免的RefCell，或者添加一个接受带有特征界限的泛型的新函数:

fn move_around<T: Walker + Swimmer>(entity: &mut T) {
    entity.walk();
    entity.swim();
}