Rust 如何将 &[T] 或 Vec<T> 转换为 Arc<Mutex<[T]>>

请考虑以下几点

use std::sync::{Arc,Mutex};

fn arc_mutex_from_slice<T>(v: &[T]) -> Arc<Mutex<[T]>> {
    todo!();
}

fn main() {
    let v = vec![1,2,3];
    println!("{:#?}", arc_mutex_from_slice(&v[..]));
}

有没有可能实施arc_mutex_from_slice？可以为Arc<Mutex<Box<[T]>>>或Arc<Mutex<Vec<T>>>实现此转换，但这两者都添加了另一个不必要的分配/间接.

类型Arc<Mutex<[T]>>是有效的，并且可以在片的大小已知时被初始化.

let x = Arc::new(Mutex::new([1,2,3]));

但当切片的大小未知时，我找不到任何方法来实现这一点.天真地try 实现arc_mutex_from_slice，如下所示不能编译.

fn arc_mutex_from_slice<T>(v: &[T]) -> Arc<Mutex<[T]>> {
    return Arc::new(Mutex::new(*v));
}

error[E0277]: the size for values of type `[T]` cannot be known at compilation time
 --> src/main.rs:4:21
  |
4 |     return Arc::new(Mutex::new(*v));
  |            -------- ^^^^^^^^^^^^^^ doesn't have a size known at compile-time
  |            |
  |            required by a bound introduced by this call
  |
  = help: within `Mutex<[T]>`, the trait `Sized` is not implemented for `[T]`
  = note: required because it appears within the type `Mutex<[T]>`
note: required by a bound in `Arc::<T>::new`

有哪unsafe种魔法能帮上忙吗？