Rust 我如何将 google_gmail1：：Gmail> 传递给线程生成

对铁 rust 来说非常陌生.我希望使用指定的查询从Gmail下载邮箱附件，我有一个粗略的同步代码，功能和我希望使用多线程使用？Tokio::Sawn？(因为项目的其余部分已经使用Tokio)当前的多线程？代码如下:

struct EmailInterface {
    pub gmail: Gmail<HttpsConnector<HttpConnector>>,
}

impl EmailInterface {
    async fn new(path_to_key: String) -> Result<EmailInterface, Box<dyn error::Error>> {
        let authenticator =
            ServiceAccountAuthenticator::builder(read_service_account_key(path_to_key).await?)
                .build()
                .await?;

        let gmail = Gmail::new(
            hyper::Client::builder().build(
                hyper_rustls::HttpsConnectorBuilder::new()
                    .with_native_roots()
                    .https_or_http()
                    .enable_http1()
                    .enable_http2()
                    .build(),
            ),
            authenticator,
        );

        Ok(EmailInterface { gmail })
    }

    pub async fn get_attachments(
        self,
        query: &str,
    ) -> Result<(), Box<dyn std::error::Error>> {
        if let Some(messages_list) = self
            .gmail
            .users()
            .messages_list("me")
            .q(query)
            .include_spam_trash(false)
            .doit()
            .await?
            .1
            .messages
        {
            let messages_id_list: Vec<String> = messages_list
                .into_iter()
                .flat_map(|message| message.id)
                .collect();

            for id in messages_id_list {
                tokio::spawn(async move {

                    let message = self.gmail
                        .users()
                        .messages_get("me", id.as_str())
                        .doit()
                        .await
                        .unwrap_or_default()
                        .1;

                    let message = self
                        .gmail
                        .users()
                        .messages_get("me", id.as_str())
                        .doit()
                        .await
                        .unwrap_or_default()
                        .1;
                    for part in message.payload {
                        if let Some(part_body) = part.body {
                            if let Some(attachment_id) = part_body.attachment_id {
                                let attachment = self
                                    .gmail
                                    .users()
                                    .messages_attachments_get(
                                        "me",
                                        id.as_str(),
                                        attachment_id.as_str(),
                                    )
                                    .doit()
                                    .await
                                    .unwrap_or_default();
                                let data = general_purpose::STANDARD
                                    .decode(&attachment.1.data.unwrap_or_default())
                                    .unwrap();
                                std::fs::write(part.filename.expect("Should have a name"), &data)
                                    .unwrap();
                            }
                        }
                    }
                });
            }
        }
        Ok(())
    }
}

我目前收到的错误

use of moved value: `self.gmail`
move occurs because `self.gmail` has type `Gmail<HttpsConnector<HttpConnector>>`, which does not implement the `Copy` trait

如果有更流畅的方式做这件事，我会洗耳恭听.

我也try 过使用ThreadPool Crate&amp；ChatGPT来寻求建议，但后者总是以错误告终.