Rust 未实现特征时返回泛型

这是我已经纠结了一段时间的代码

use ethers_providers::{Provider, Http}; //, JsonRpcClient};

// this doesn't work
// trait ClientGeneric<T> {
//     fn get_client(&self, url:&str) -> Provider<T> {
//         Provider::<T>::try_from(url).unwrap()
//     }
// }
// this works but I want generic
trait ClientConcrete {
    fn get_client(&self, url:&str) -> Provider<Http> {
        Provider::<Http>::try_from(url).unwrap()
    }
}
struct Test;
impl ClientConcrete for Test {}

#[cfg( test )]
mod tests {
    use super::*;
    // #[test]
    // fn test_get_client_generic() {
    //     let test = Test{};
    //     let client = test.get_client("http://localhost:8080");
    // }
    #[test]
    fn test_get_client_concrete() {
        let test = Test{};
        let client = test.get_client("http://localhost:8080");
    }
}

我希望 for each 传输T返回Provider<T>:http、ws、ipc、mock等 通常，每个传输都实现了TryFrom特征.然而，上面的代码不适用于泛型T，即使它适用于具体的传输.对于泛型T，我收到的错误:

error[E0277]: the trait bound `Provider<T>: From<&str>` is not satisfied
 --> src/test.rs:6:9
  |
6 |         Provider::<T>::try_from(url).unwrap()
  |         ^^^^^^^^^^^^^^^^^^^^^^^ the trait `From<&str>` is not implemented for `Provider<T>`
  |
  = help: the following other types implement trait `TryFrom<T>`:
            <Provider<Http> as TryFrom<&'a String>>
            <Provider<Http> as TryFrom<&str>>
            <Provider<Http> as TryFrom<String>>
  = note: required because of the requirements on the impl of `Into<Provider<T>>` for `&str`
  = note: required because of the requirements on the impl of `TryFrom<&str>` for `Provider<T>`

不幸的是，在类型T上没有匹配语句，我可以使用(就像在Golang中一样)来实现具体的类型. 据我所知，我不能为外来 struct Provider<T>实现外来特性TryFrom<&str>.TryFrom<&str>是为基础类型Http、Ws、Ipc等实现的

还有什么我能做的吗？