我有一个lifetime个问题,我试图实现一个迭代器,通过引用返回它的项,下面是代码:
struct Foo {
d: [u8; 42],
pos: usize
}
impl<'a> Iterator<&'a u8> for Foo {
fn next<'a>(&'a mut self) -> Option<&'a u8> {
let r = self.d.get(self.pos);
if r.is_some() {
self.pos += 1;
}
r
}
}
fn main() {
let mut x = Foo {
d: [1; 42],
pos: 0
};
for i in x {
println!("{}", i);
}
}
然而,这段代码没有正确编译,我遇到了一个与参数生命周期有关的问题,下面是相应的错误:
$ rustc test.rs
test.rs:8:5: 14:6 error: method `next` has an incompatible type for trait: expected concrete lifetime, but found bound lifetime parameter
test.rs:8 fn next<'a>(&'a mut self) -> Option<&'a u8> {
test.rs:9 let r = self.d.get(self.pos);
test.rs:10 if r.is_some() {
test.rs:11 self.pos += 1;
test.rs:12 }
test.rs:13 r
...
test.rs:8:49: 14:6 note: expected concrete lifetime is the lifetime 'a as defined on the block at 8:48
test.rs:8 fn next<'a>(&'a mut self) -> Option<&'a u8> {
test.rs:9 let r = self.d.get(self.pos);
test.rs:10 if r.is_some() {
test.rs:11 self.pos += 1;
test.rs:12 }
test.rs:13 r
...
error: aborting due to previous error
有人知道如何解决这个问题,并且仍然通过引用返回项目吗?
至少这个信息意味着什么:expected concrete lifetime, but found bound lifetime parameter?