我有一个散列数组，我试图断言该数组有exactly a certain number个散列，其中certain order的散列值为certain key.

假设我有一系列的水果.

fruits = [
  { name: 'apple', count: 3 },
  { name: 'orange', count: 14 },
  { name: 'strawberry', count: 7 },
]

当我对hash_including(或其别名include)使用eq匹配器时，断言失败.

# fails :(
expect(fruits).to eq([
  hash_including(name: 'apple'),
  hash_including(name: 'orange'),
  hash_including(name: 'strawberry'),
])

奇怪的是，这不起作用，我总是能找到解决方法，然后继续前进，但它已经困扰了我一段时间，所以我决定这次把它贴出来.

What I'm not looking for

显然，这是可行的，但我喜欢另一种语法，因为这是这些匹配器的要点:所以我不必手动转换我的数据 struct ，并且具有更好的可读性.

fruit_names = fruits.map { |h| h.fetch(:name) }
expect(fruit_names).to eq(['apple', 'orange', 'strawberry'])

contain_exactly和include可以工作，但我关心的是数组的exact size和元素的order，它们未能断言.

# passes but doesn't assert the size of the array or the order of elements
expect(fruits).include(
  hash_including(name: 'apple'),
  hash_including(name: 'orange'),
  hash_including(name: 'strawberry'),
)

# passes but doesn't assert the exact order of elements
expect(fruits).contain_exactly(
  hash_including(name: 'apple'),
  hash_including(name: 'orange'),
  hash_including(name: 'strawberry'),
)