从文本库中的屏幕内部切换模式Python

发布于01月17日

在Textual，我有一个应用程序，有3种模式.但是，我想根据用户输入切换屏幕内的模式.我怎么才能做到这一点呢？ App.py:

class DemoApp(App[None]):
MODES = {
        "profile": ProfileScreen,
        "chat": ChatScreen,
        "help": HelpScreen,
        }
    def on_mount(self) -> None:
        """On running"""
        LOGGER.info("Starting")
        self.switch_mode("chat")
class ChatScreen(Screen):
    def compose(self) -> ComposeResult:
        yield Button(label="Profile", variant="success", id="change_profile")

    async def on_button_pressed(self) -> None:
        await self.process()

    async def process():
        switch_mode("profile")  # How do I do this?

我在谷歌上搜索了所有内容，并阅读了相关文档.但我还是找不到解决办法.

推荐答案

您可以通过app property获取正在运行的App实例，所以只需:

async def process(self):
    self.app.switch_mode("profile")

请注意，您忘记了process实例方法中的self参数.

一个可重复的例子:

from textual.app import App, ComposeResult
from textual.screen import Screen
from textual.widgets import Button


class ChatScreen(Screen):
    def compose(self) -> ComposeResult:
        yield Button(label="Profile", variant="success", id="change_profile")

    async def on_button_pressed(self) -> None:
        self.app.switch_mode("profile")


class ProfileScreen(Screen):
    def compose(self) -> ComposeResult:
        yield Button(label="Help", variant="success", id="change_profile")

    async def on_button_pressed(self) -> None:
        self.app.switch_mode("help")


class HelpScreen(Screen):
    def compose(self) -> ComposeResult:
        yield Button(label="Chat", variant="success", id="change_profile")

    async def on_button_pressed(self) -> None:
        self.app.switch_mode("chat")


class DemoApp(App[None]):
    MODES = {
            "profile": ProfileScreen,
            "chat": ChatScreen,
            "help": HelpScreen,
            }

    def on_mount(self) -> None:
        """On running"""
        # LOGGER.info("Starting")
        self.switch_mode("chat")


if __name__ == "__main__":
    app = DemoApp()
    app.run()