Python—压缩叶 map html作为邮箱附件并通过sendgrid发送

发布于03月26日

我试图压缩叶 map html，以减少大小，以附加到邮箱发送通过Sendgrid.

map_content = m.get_root().render()
zip_buffer = io.BytesIO()
with zipfile.ZipFile(zip_buffer, 'w', zipfile.ZIP_DEFLATED) as zipf:
        zipf.writestr("event_map.html", map_content.encode('utf-8'))
        zip_buffer.seek(0)

attachments = [location_attachment, coverage_attachment, zip_buffer.getvalue()]
filenames = [
            "Raw Data 1.csv",
            "Data 2.csv",
            "event_map.zip"
        ]
filetypes = ["text/csv", "text/csv", "application/zip"]

此代码允许我创建zip并通过邮箱发送，但zip附件无法打开，Windows抛出无效Zip错误.

有人能提出一个解决办法吗？

谢谢你

推荐答案

似乎问题可能是在将 map 内容添加到zip文件之前如何对其进行编码.在将内容添加到zip文件之前，不要对其进行编码，而应该直接将其添加为字节.以下是您代码的更正版本:

import folium
import io
import zipfile
import sendgrid
from sendgrid.helpers.mail import (
    Attachment,
    FileContent,
    FileName,
    FileType,
    Disposition,
    ContentId,
    Email,
    Mail,
)

# Assuming you already have 'm' defined as your Folium map object
map_content = m.get_root().render()
zip_buffer = io.BytesIO()

with zipfile.ZipFile(zip_buffer, 'w', zipfile.ZIP_DEFLATED) as zipf:
    zipf.writestr("event_map.html", map_content)

# Reset buffer position to beginning
zip_buffer.seek(0)

# Prepare SendGrid attachments
attachments = [
    Attachment(
        FileContent(zip_buffer.getvalue()),
        FileName("event_map.zip"),
        FileType("application/zip"),
        Disposition('attachment')
    )
]