Python Pygame按钮点击和if语句

我刚开始一段时间后，有一些问题，有点迷失.

一直在try 用图像作为按钮在Electron 游戏中制作菜单.在看了其他人之后，我模糊了大部分内容，但我认为我犯了一个愚蠢的错误，弄不明白--砍掉了很多行.第一个按钮起作用了，会把你带到正确的菜单，但其他按钮都没有注册.

大多数向导使用绘制来创建按钮，因此没有什么帮助.

Similar but uses draw个

我try 移动If\Elif\Else语句，但出现错误或什么都不起作用.

不是真正的程序员，只是想要一些东西来把我们的D&amp；Dbrew 软件结合在一起--以前使用过TKint，但我想我会试一试.

import pygame
from pygame import mixer
 
pygame.init()
width=900;
height=800
screen = pygame.display.set_mode( (width, height ) )
pygame.display.set_caption('Chapter 1')
#TownMap = pygame.image.load("Data/images/town.png").convert()
#Button = pygame.image.load("Data/images/buttonsSolo.png").convert_alpha()

def Main_Menu():  

  Back_Drop = pygame.image.load("Data/images/Art/cursewick1.jpg").convert()
  Start_Button = pygame.image.load("Data/Images/UI/Buttons/Start.png").convert_alpha() 
  Help_Button = pygame.image.load("Data/Images/UI/Buttons/Help.png").convert_alpha() 
  Exit_Button = pygame.image.load("Data/Images/UI/Buttons/Exit.png").convert_alpha() 
  screen.blit(Back_Drop, (0,0))
  screen.blit(Start_Button ,  ( 10,10)) # paint to screen
  screen.blit(Help_Button ,  ( 10,110)) # paint to screen
  screen.blit(Exit_Button ,  ( 10,210)) # paint to screen
  pygame.display.flip() # paint screen one time
  
  mixer.init()
  mixer.music.load("Data\Audio\Music\Intro.mp3")
  pygame.mixer.music.set_volume(0.1)
  mixer.music.play()
  
  
  running = True
  while (running):  
  
      for event in pygame.event.get():
          if event.type == pygame.QUIT:
              running = False
          if event.type == pygame.MOUSEBUTTONDOWN:
              # Set the x, y postions of the mouse click
              x, y = event.pos
              if Start_Button.get_rect().collidepoint(x, y):
                  print('clicked on image')
                  pygame.mixer.music.pause()
                  Town_Map()
              if Help_Button.get_rect().collidepoint(x, y):
                  print('Help')
                  pygame.mixer.music.pause()
                      
                  

  #loop over, quite pygame
  pygame.quit()