Python 我怎么才能在PYGAME中制作电池电表呢

你只有3张图片.要么你需要更多的图像，要么你必须在PYGAME中绘制比例.下面是一段在图像上绘制动态比例的简单代码.刻度盘只是一个矩形，其高度随电池电量的变化而变化:

import pygame

pygame.init()
screen = pygame.display.set_mode((300, 200))
clock = pygame.time.Clock()

battery_image_v = pygame.Surface((50, 100))
battery_image_v.fill("darkgray")
pygame.draw.rect(battery_image_v, "black", (18, 3, 14, 94))
scale_image_v = pygame.Surface((10, 90))

battery_image_h = pygame.Surface((100, 50))
battery_image_h.fill("darkgray")
pygame.draw.rect(battery_image_h, "black", (3, 18, 94, 14))
scale_image_h = pygame.Surface((90, 10))

battery = 100

run = True
while run:
    clock.tick(100)
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False 
    
    battery -= 1
    if battery < 0:
        battery = 100

    scale_image_v.fill("black")
    h = battery * scale_image_v.get_height() // 100
    y = scale_image_v.get_height() - h
    pygame.draw.rect(scale_image_v, "green", (0, y, 10, h))

    scale_image_h.fill("black")
    w = battery * scale_image_h.get_width() // 100
    pygame.draw.rect(scale_image_h, "green", (0, 0, w, 10))

    screen.fill("white")
    screen.blit(battery_image_v, battery_image_v.get_rect(center = (100, 100)))
    screen.blit(scale_image_v, scale_image_v.get_rect(center = (100, 100)))
    screen.blit(battery_image_h, battery_image_h.get_rect(center = (200, 100)))
    screen.blit(scale_image_h, scale_image_h.get_rect(center = (200, 100)))
    pygame.display.flip()

pygame.quit()
exit()