Python中用于匹配URL并从URL中提取部分的正则表达式

与Aymen Azouis解决方案非常相似，只是做了一些小的优化.

1. 使用regex个库，哪个IMHO比re更好
2. 可 Select 检测http://和https://
3. 所有格量词

(?x)
^                                  # start of pattern
https?                             # http with an optinal s
://
(?P<artifactory_instance>[^/:]++)  # capture everythin up to the next ":" or "/"
(?::\d++)?                         # if you encounter a port match it (optional)
/artifactory/
(?P<repository>[^/]++)             # match repository by capturing everything up to next "/"
/
(?P<artifact_names>.++)            # match the rest of URL to artifact names
$

在regexre(https://regexre.com/r/7Ww4ui/1)上省略了所有格限定符，因为re模块不处理它们(这是在rexexre上实现的).

或作为可执行代码:

import regex 

def extract_artifactory_data(url):
    pattern = r"^https?://(?P<artifactory_instance>[^/:]++)(?::\d++)?/artifactory/(?P<repository>[^/]++)/(?P<artifact_names>.++)$"
    match = regex.match(pattern, url)
    
    if not match:
        return None
    
    return match.group("artifactory_instance"), match.group("repository"), match.group("artifact_names")

url1 = "https://artifactory.intuit.veg.com:443/artifactory/annual-budget-local/manifests-approved/1.0.0/annual-chart/po09ij/annual-f3c.tgz"
url2 = "https://artifactory.skopeo.marvel.org/artifactory/bulletins_virtual/manifests-approved/po09ij/annual-f3c.tgz"

instance1, repo1, artifact1 = extract_artifactory_data(url1)
instance2, repo2, artifact2 = extract_artifactory_data(url2)

print(instance1, repo1, artifact1)
print(instance2, repo2, artifact2)