Python 在matplotlib中绘制六角形的每个顶点和交点处的标签

你的三角形不是闭合的，因此你在triangles中有两个以上的三角形(六角星形是).您应该构建完整的三角形，这样您甚至可以将您的代码推广到任何大小的尖星(只要它是3的倍数).

我用shapely来计算交叉点:

import matplotlib.pyplot as plt
import math
from shapely import Polygon, get_coordinates

def plot_hexagram_with_numbers(side_length, nb_points=6):
    if nb_points % 3:
        raise ValueError("nb_points must be a multiple of 3")
    # Calculate the coordinates for the vertices of the hexagram
    vertices = []
    mu_hexagon = 360 / nb_points
    for i in range(nb_points):
        angle_rad = math.radians(i * mu_hexagon)
        x = side_length * math.cos(angle_rad)
        y = side_length * math.sin(angle_rad)
        vertices.append((x, y))

    # Create a list of triangles' vertices and plot triangles
    triangles = []
    nb_triangles = nb_points//3
    for i in range(nb_triangles):
        triangle = [vertices[i], vertices[i + nb_triangles], vertices[i + 2*nb_triangles], vertices[i]]
        plt.plot(*zip(*triangle), 'b-')
        triangles.append(Polygon(triangle))

    # computing intersections
    intersections = [] 
    for i in range(nb_triangles):
        for j in range(i+1, nb_triangles):
            intersections.extend(get_coordinates(triangles[i].intersection(triangles[j]))[:-1])

    # Add numbers at each vertex and intersection of the hexagram
    for i, (x,y) in enumerate(vertices + intersections, start=1):
        plt.annotate(i, (x,y))

    # Set axis equal and show the plot
    plt.axis('equal')
    plt.show()

输出(默认为nb_points=6):

输出(nb_points=9):