我想用for Cycle分析已经绘制在情节上的线.我try 使用ax.get_lines()[0].get_data()函数，但无论我绘制哪种类型的直线(它通过哪些点)，它都会返回([0, 1], [0, 1])作为数据.
import numpy as np
import matplotlib.pyplot as plt
plt.rcParams["figure.figsize"] = [7.00, 7.00]
fig = plt.figure()
ax = fig.add_subplot(111)
ax.set_xlim([0, 100])
ax.set_ylim([0, 100])
point1 = [-8,4]
point2 = [10,15]
plt.axline(point1,point2) # drawing the line
lines = ax.get_lines()
print(lines[0].get_data()) # retrieving data
plt.show()
我查看了各种资源中get_lines()的用法，它似乎被用来获得(在文献中)的行数.如下所示:
lines = ax.get_lines()
print('number of lines', len(lines))
如果您想要获得两点之间的(straight)线的描述(presumably slope and intercept)，您可以使用如下的简单函数来实现结果:
def get_slope_and_intercept(point1, point2):
"""
Gets the slope and intercept of the line given point1 and point2 as two lists.
Args:
point1: The first point, as a list of two numbers.
point2: The second point, as a list of two numbers.
Returns:
A tuple of the slope and intercept of the line.
"""
x1, y1 = point1
x2, y2 = point2
slope = (y2 - y1) / (x2 - x1)
intercept = y1 - slope * x1
return slope, intercept
if __name__ == "__main__":
slope, intercept = get_slope_and_intercept(point1, point2)
print("The slope is:", slope)
print("The intercept is:", intercept)
考虑到问题中给出的几点，它将产生以下结果:
The slope is: 0.6111111111111112
The intercept is: 8.88888888888889