Python 如何找到可以形成一个列表的数值以及如何将答案 struct 化为另一个列表

#Given the following 2 example tables (always both tables have the same dimensions)

tabla_ganancias = [[5, 6, 3, 5, 5], 
                   [2, 5, 3, 1, 0], 
                   [2, 4, 0, 1, 1]]

tabla_asignaciones = [[ 140,  220, None,   80,   60], 
                      [None, None,  330, None, None], 
                      [None, None,   30, None,   90]]

tabla_resultado = []
rows = len(tabla_ganancias)
columns = len(tabla_ganancias[0])

#Code that creates result_table and does the decomposition of the profits
#HERE THE PROBLEM

#Print the results obtained
print(tabla_resultado)
for lista in tabla_resultado: print(lista)

我分解了与tabla_assignments的非空单元格对应的值tabla_ganancias(即，它们不是无)，将收入值的分解放在最后一行和最后一列.

在这种情况下，利润的价值将被分解(通过分解，我的意思是找到两个加起来构成的整数):

增益值5在行中变为2，在列中变为3->2+3=5

增益值6在一行中变为2，在一列中变为4-->2+4=6

增益值5在行中变为2，在列中变为3->2+3=5

增益值5在行中变为2，在列中变为3->2+3=5

增益值3在一行中变为1，在列中变为2->1+2=3

增益值0在行中变为2，在列中变为-2-->2+(-2)=0

增益值1在行中变为-2，在列中变为3-2+3=1

因此，结果表的最后一行和最后一列中包含利润分解.请注意，tabla_resultado是tabla_asignaciones，但带有利润分解的行和列

#The decomposed values will be stored in the last row and last column of tabla_resultado.


#System of equations that should be solved to find the values that I need to build the last of the rows and the last of the columns of tabla_resultado
# X1 + Y1 = 5
# X2 + Y1 = 6
# X4 + Y1 = 5
# X5 + Y1 = 5
# X3 + Y2 = 3
# X3 + Y3 = 0
# X5 + Y3 = 1

#tabla_resultado = [[ 140,  220, None,   80,   60,    Y1], 
#                   [None, None,  330, None, None,    Y2], 
#                   [None, None,   30, None,   90,    Y3], 
#                   [  X1,   X2,   X3,   X4,   X5,  None]]

tabla_resultado = [[ 140,  220, None,   80,   60,    2], 
                   [None, None,  330, None, None,    1], 
                   [None, None,   30, None,   90,   -2], 
                   [   3,    4,    2,    3,    3, None]]

这段代码不起作用，但我添加以下内容

#Given the following 2 example tables (always both tables have the same dimensions)

tabla_ganancias = [[5, 6, 3, 5, 5], 
                   [2, 5, 3, 1, 0], 
                   [2, 4, 0, 1, 1]]

tabla_asignaciones = [[ 140,  220, None,   80,   60], 
                      [None, None,  330, None, None], 
                      [None, None,   30, None,   90]]


tabla_resultado = []
rows = len(tabla_ganancias)
columns = len(tabla_ganancias[0])

for i in range(rows):
    tabla_resultado.append([])
    for j in range(columns):
        if tabla_asignaciones[i][j] is not None:
            value = tabla_ganancias[i][j]
            x = value // 2
            y = value - x
            tabla_resultado[i].append(x)
            if len(tabla_resultado) <= j+rows:
                tabla_resultado.append([None] * (rows+1))
            tabla_resultado[i][j+rows] = y
        else:
            tabla_resultado[i].append(None)

# Print the results obtained
print(tabla_resultado)
for lista in tabla_resultado: print(lista)

但我明白这个错误

Traceback (most recent call last):
    tabla_resultado[i][j+rows] = y
IndexError: list assignment index out of range

Become the problem to System of Linear Equations