我有以下代码作为示例:
x=[1,2,3,4]
y=[2,2,4,3]
colors = ["blue","blue","orange","blue"]
textures = ["","","x",""]
myfig = go.Figure()
myfig.add_trace(go.Bar(x=x
,y=y
,showlegend=True
,marker_color=colors
,marker_pattern_shape=textures
,name="my_trace"))
myfig.show()
这将产生以下数字:
我想让图例显示两个名字:
我不能给情节增加更多的痕迹，关键是要用同样独特的痕迹来做.
我认为plotly express个在这里会很好用.除了color之外，您还需要使用color_discrete_map，因为Ploly不会将您的 colored颜色 列表解释为 colored颜色 ，而是将其解释为唯一字符串(并 for each 唯一字符串分配其自己的默认 colored颜色 ，而不考虑字符串本身).因此，我们要做的是创建一个名称列表(用于图例)以传递给 colored颜色 参数，然后使用color_discrete_map将每个名称映射到实际 colored颜色 .
类似地，除了pattern_shape之外，您还需要为pattern_shape_sequence提供一个参数，因为Pattery_Shape_Sequence将用来指定实际纹理.
import numpy as np
import plotly.express as px
import plotly.graph_objects as go
x=[1,2,3,4]
y=[2,2,4,3]
names = ["any","any","max","any"]
colors = ["blue","blue","orange","blue"]
color_discrete_map = {n:c for n,c in zip(names, colors)}
textures = ["","","x",""]
textures_sequence = np.unique(textures).tolist() # ['', 'x']
myfig = px.bar(x=x, y=y, color=names, color_discrete_map=color_discrete_map, pattern_shape=textures, pattern_shape_sequence=textures_sequence)
myfig.show()
