Python 查找列表内的所有元组组合

perm = [(3, 6), (6, 8), (4, 1), (7, 4), (5, 3),
        (1, 9), (2, 5), (4, 8), (5, 1), (3, 7),
        (6, 9), (10, 2), (7, 10), (8, 2), (9, 10)]

perm = [(6, 3), (6, 8), (4, 1), (7, 4), (5, 3),
        (1, 9), (2, 5), (4, 8), (5, 1), (3, 7),
        (6, 9), (10, 2), (7, 10), (8, 2), (9, 10)]

perm = [(6, 3), (8, 6), (1, 4), (4, 7), (3, 5),
        (9, 1), (5, 2), (8, 4), (1, 5), (7, 3),
        (9, 6), (2, 10), (10, 7), (2, 8), (10, 9)]

from itertools import product

lst = [(3, 6), (6, 8), (4, 1), (7, 4), (5, 3),
       (1, 9), (2, 5), (4, 8), (5, 1), (3, 7),
       (6, 9), (10, 2), (7, 10), (8, 2), (9, 10)]

output = product(*([(x, y), (y, x)] for x, y in lst))

output = list(output) # if you want a list, rather than a generator

print(len(output))
# 32768

print(output[0])
# ((3, 6), (6, 8), (4, 1), (7, 4), (5, 3), (1, 9), (2, 5), (4, 8), (5, 1), (3, 7), (6, 9), (10, 2), (7, 10), (8, 2), (9, 10))
print(output[-1])
# ((6, 3), (8, 6), (1, 4), (4, 7), (3, 5), (9, 1), (5, 2), (8, 4), (1, 5), (7, 3), (9, 6), (2, 10), (10, 7), (2, 8), (10, 9))

output = product([(3,6), (6,3)], [(6,8), (8,6)], ..., [(9,10), (10,9)])

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