Python 用于在日期中提取月份和年份组合的正则表达式

regex = (
    r"((Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|Jun(e)?|Jul(y)?|Aug(ust)?|Sep(tember)?(t)?|Oct(ober)?|Nov(ember)?|Dec(ember)?)"
    r"\s?[\.\s\’\’\,\/\'\,\‘\-\–\—]?\s?(\d{4}|\d{2})?\s?\s?((to)|[\|\-\–\—])\s?\s?"
    r"((Jan(uary)?|Feb(ruary)?|Mar(ch)?|Apr(il)?|May|Jun(e)?|Jul(y)?|Aug(ust)?|Sep(tember)?(t)?|Oct(ober)?|Nov(ember)?|Dec(ember)?)"
    r"\s?[\.\s\’\’\,\/\'\,\‘\-\–\—]?\s?(\d{4}|\d{2})|(Present|Now|till\s?(now|date|today)?|current)))"
)

lst = [
    'July 2014 - 28th August 2014',
    'Jan 2012 - 3rd sep 2014',
    'Jan 2008 - May 2012',
    'Jan 2008 and May 2012'
]
for i in lst:
    word = re.finditer(regex,i,re.IGNORECASE)
    for match in word:
        print(match.group())

Jan 2008 - May 2012

July 2014 - August 2014
Jan 2012 - sep 2014
Jan 2008 - May 2012

import re


day = r'(?:((?:0?[1-9]|[12]\d|3[01])(?:\s*(?:st|[rn]d|th))?)\s*)?'
month = r'(Jan(?:uary)?|Feb(?:ruary)?|Mar(?:ch)?|Apr(?:il)?|May|June?|July?|Aug(?:ust)?|Sep(?:t(?:ember)?)?|Oct(?:ober)?|Nov(?:ember)?|Dec(?:ember)?)' 
year = r'(\d{2}(?:\d{2})?)'
rx_valid = re.compile( fr'\b{day}{month}\s*{year}\s*[-—–]\s*{day}{month}\s*{year}(?!\d)', re.IGNORECASE )
rx_ordinal = re.compile( r'\s*\d+\s*(?:st|[rn]d|th)', re.IGNORECASE )

lst = [
    'July 2014 - 28th August 2014',
    'Jan 2012 - 3rd sep 2014',
    'Jan 2008 - May 2012',
    'Jan 2008 and May 2012'
]
for i in lst:
    word = rx_valid.finditer(i)
    for match in word:
        print(rx_ordinal.sub("", match.group()))

July 2014 - August 2014
Jan 2012 - sep 2014
Jan 2008 - May 2012

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