Python 将 (x,y) 坐标列表设置为数组，以便绘制多边形

我有一些代码可以打印出坐标列表(存储在点中)

f=open('139cm_2000_frame27.json') 
data=json.load(f) 
shapes=data["shapes"] 
for i in shapes: 
    print(i['label'])   # prints the label first
    for c in i['points']:
        d=np.array(c)
        print(d)       # an array containing coordinates in the form (x,y) 

d、 坐标是n个10边多边形的点.坐标0-9是第一个多边形的坐标，坐标10-19是第二个多边形...

json文件中可以有任意数量的多边形，但每个多边形始终有10个坐标.

我需要找到一种方法，使用这些坐标在128x128数组中"绘制"或"重建"这些多边形.

我试过了

from skimage.draw import polygon
   img = np.zeros((128, 128), dtype=np.uint8)
   r = np.array([#the x coordinates of d])
   c = np.array([#the y coordinates of d])
   rr, cc = polygon(r, c)
   img[rr, cc] = 1 #unsure about the 1
   img

但我不知道如何1)获得10个坐标集，2)将xs读入r，将ys读入c

非常感谢！

输入json的一个示例:

{
  "version": "4.6.0",
  "flags": {},
  "shapes": [
    {
      "label": "blob",
      "points": [
        [
          61.42857142857143,
          20.285714285714285
        ],
        [
          59.10047478151446,
          18.879430437885873
        ],
        [
          58.04359793578868,
          16.37330203102605
        ],
        [
          58.661631924538575,
          13.724584936383643
        ],
        [
          60.71850877026435,
          11.94499905752918
        ],
        [
          63.42857142857143,
          11.714285714285715
        ],
        [
          65.75666807562841,
          13.120569562114127
        ],
        [
          66.81354492135418,
          15.62669796897395
        ],
        [
          66.19551093260428,
          18.275415063616357
        ],
        [
          64.13863408687851,
          20.05500094247082
        ]
      ],
      "group_id": null,
      "shape_type": "polygon",
      "flags": {}
    },
    {
      "label": "blob",
      "points": [
        [
          88.71428571428572,
          82.42857142857143
        ],
        [
          85.63470409582908,
          81.33512050565437
......