Python 从嵌套的yaml创建一个嵌套字符串，后面跟着点

我在yaml中有一个输入，包含不同级别的嵌套对象.我需要一个Python函数来判断所有的并获得所需的输出—字符串列表，其中每个字段被点分隔，如果嵌套—Object1.Object2.Object3.Object4...下面的例子.

我试图用递归函数来实现它.我的代码片段:

tests = []
test2 = {}
def test(config, parent=None):
    previous_parent = None
    names = []
    for column in config:
    
        if column.get("dtype") in ["array", "struct"]:
            parent = column["name"]
            print(f"parent: {parent}")
            test(column["columns"], parent)
            
        else:
            value = column["name"]
            print(f"value: {value}")
            # names.append(value)

输出是:

value: PartitionDate
value: TransactionID
value: EventTimestamp
parent: ControlTransaction
value: StoreID
parent: RetailTransaction
value: StoreID
value: WorkstationID
...

输入:

columns:
- name: PartitionDate
- name: TransactionID
- name: EventTimestamp
- name: ControlTransaction
  dtype: struct
  columns:
    - name: StoreID
    - name: WorkstationID
    - name: Transaction
      dtype: struct
      columns:
        - name: TransactionID
    - name: TransactionNumber
- name: ControlType
- name: RetailTransaction
  dtype: struct
  columns:
    - name: StoreID
    - name: WorkstationID

输出:

[
PartitionDate,
TransactionID,
EventTimestamp,
ControlTransaction.StoreID,
ControlTransaction.WorkstationID,
ControlTransaction.Transaction.TransactionID,
ControlTransaction.TransactionNumber,
ControlType,
RetailTransaction.StoreID,
RetailTransaction.WorkstationID
]