在Python2.7中有一个读取zip文件中的CSV文件的简单程序,但在Python3.2中没有
$ cat test_zip_file_py3k.py
import csv, sys, zipfile
zip_file = zipfile.ZipFile(sys.argv[1])
items_file = zip_file.open('items.csv', 'rU')
for row in csv.DictReader(items_file):
pass
$ python2.7 test_zip_file_py3k.py ~/data.zip
$ python3.2 test_zip_file_py3k.py ~/data.zip
Traceback (most recent call last):
File "test_zip_file_py3k.py", line 8, in <module>
for row in csv.DictReader(items_file):
File "/home/msabramo/run/lib/python3.2/csv.py", line 109, in __next__
self.fieldnames
File "/home/msabramo/run/lib/python3.2/csv.py", line 96, in fieldnames
self._fieldnames = next(self.reader)
_csv.Error: iterator should return strings, not bytes (did you open the file
in text mode?)
因此,Python 3中的csv
模块希望看到一个文本文件,但zipfile.ZipFile.open
返回一个始终被视为二进制数据的zipfile.ZipExtFile
.
如何在Python 3中实现这一点?