PHP Loop 在迭代中使用修改后的数据

我有一个如下所示的数组

Array
(
[0] => Array
    (
        [id] => 9
        [needed_at] => 2023-02-26 03:31:04
        [ended_at] => 2023-02-26 04:31:04
        [add] => 20
    )

[1] => Array
    (
        [id] => 6
        [needed_at] => 2023-02-26 04:51:04
        [ended_at] => 2023-02-26 05:51:04
        [add] => 30
    )

[2] => Array
    (
        [id] => 7
        [needed_at] => 2023-02-26 09:21:04
        [ended_at] => 2023-02-26 10:21:04
        [add] => 30
    )

)

现在在一个循环中，我想修改0索引中的ended_at，然后使用这个修改后的ended_at来替换1索引中的needed_at.在这种方式下，还想用1个索引的修改后的ended_at等替换2个索引

我试过的是

foreach($jobs as $k => $j){
            $s = $k+1;
            $date = new \DateTimeImmutable($j->ended_at);
            $add = $j->add;
            $date_new = $date->modify('+'.$add.' minutes');
            $needed_at = $date_new->format('Y-m-d H:i:s');
            $data['needed_at'] = $needed_at;
            
            $date2 = new \DateTimeImmutable($needed_at);
            $ended_at = $date2->modify('+60 minutes');
            $data['ended_at'] = $ended_at->format('Y-m-d H:i:s');

                $d[]=[
                    'id' => $jobs[$s]->id,
                    'needed_at' => $needed_at,
                    'ended_at' => $data['ended_at'],
                    'add' => $add
                ];

}

这不管用.是否可以将第一次迭代修改后的数据用于第二次迭代？需要帮助

我的预期结果是

Array
(
[0] => Array
    (
        [id] => 9
        [needed_at] => 2023-02-26 03:31:04
        [ended_at] => 2023-02-26 04:31:04
        [add] => 20
    )

[1] => Array
    (
        [id] => 6
        [needed_at] => 2023-02-26 04:51:04
        [ended_at] => 2023-02-26 05:51:04
        [add] => 30
    )

[2] => Array
    (
        [id] => 7
        [needed_at] => 2023-02-26 06:21:04
        [ended_at] => 2023-02-26 07:21:04
        [add] => 30
    )

)