Php Google Drive 仅使用 FileID 获取文件的 FileSize

我只需要使用Google Drive FileID来获取文件的元数据.假设我不知道FolderID.通过仅使用FileID，API只为filesize返回null，但为其他元数据返回正确的值.

为了清楚起见，我可以通过处理文件夹中的文件来获取所有元数据(包括文件大小)，例如:

<?php
/*
* With this example I have the folderID from a Google Drive shared link
*/

 $folderId = "https://drive.google.com/drive/folders/1ggWcacF9qQroZOkhfb3tTEwvBzclccwI?usp=share_link";
 $Auth = new Oauth2Authentication();
 $client = $Auth->GetClient();
 $client = $Auth->initializeClient($client);
 $drive = new DriveService($client);
 $pattern = "/[-\w]{25,}(?!.*[-\w]{25,})/";
 if (preg_match($pattern, $folderId, $match)); // grabs folderID from the url
 
 /*
  * Now list the folder contents
 */
 $responseFiles = $drive->ListFiles($match[0]);
 $files = $responseFiles['files'];
 foreach ($files as $file) {
     $id[] = $file->id;
     $name[] = $file->name;
     $mimeType[] = $file->mimeType;
     $size[] = $file->size; //<- correct file size
 };
 $drive->DownloadFile($id, $name, $size);

下面的代码是我需要使用的，它返回大多数元数据，但如上所述，$file->size始终是null.我的DownloadFile方法需要文件大小，这样它才能更好地处理大文件.有谁能帮我更好地理解这个问题吗？

<?php
/*
* With this example I have the only the fileID from a Google Drive shared link
*/

 $fileId = "https://drive.google.com/file/d/1EjNk1ijPLKJMwXfzkEIG487HFzx0v80v/view?usp=share_link";
 $Auth = new Oauth2Authentication();
 $client = $Auth->GetClient();
 $client = $Auth->initializeClient($client);
 $drive = new DriveService($client);
 $pattern = "/[-\w]{25,}(?!.*[-\w]{25,})/";
 if (preg_match($pattern, $fileId, $match)); // grabs fileID from the url
 /*
  * Now get the file meta data and download the file
 */
 $fileId = $match[0];
 $service = new Google_Service_Drive($client);
 $file = $service->files->get($fileId);
 $drive->DownloadFile($file->id, $file->name, $file->size);  //$file->size is always null

Update:感谢@DaImto，我被指向了正确的方向.完整的fileID的详细信息可以通过添加

array('fields' =>'*')

添加到$service->files->get方法的参数列表，即

$file = $service->files->get($fileId,array('fields' =>'*'));