On the official API doc, it says:
以整数形式返回此数字的值，这可能涉及舍入或截断.
我想要截断，但不确定.有人能解释may involve rounding or truncation的确切含义吗？
p.s.: In my unit test, (1.7).toInt() was 1, which might involve truncation.
On the official API doc, it says:
以整数形式返回此数字的值，这可能涉及舍入或截断.
我想要截断，但不确定.有人能解释may involve rounding or truncation的确切含义吗？
p.s.: In my unit test, (1.7).toInt() was 1, which might involve truncation.
The KDoc of Double.toInt() is simply inherited from Number.toInt(), and for that, the exact meaning is, it is defined in the concrete Number implementation how it is converted to Int.
在Kotlin中，Double运算遵循IEEE 754标准，Double.toInt()转换的语义与casting double to int in Java相同，即正常数向零舍入，舍go 小数部分:
println(1.1.toInt()) // 1
println(1.7.toInt()) // 1
println(-2.3.toInt()) // -2
println(-2.9.toInt()) // -2