将一个字符串拆分成每个字符串2个字符的惯用方式是什么？
Examples:
"" -> [""]
"ab" -> ["ab"]
"abcd" -> ["ab", "cd"]
我们可以假设字符串的长度是2的倍数.
I could use a regex like in this Java answer but I was hoping to find a better way (i.e. using one of kotlin's additional methods).
将一个字符串拆分成每个字符串2个字符的惯用方式是什么？
Examples:
"" -> [""]
"ab" -> ["ab"]
"abcd" -> ["ab", "cd"]
我们可以假设字符串的长度是2的倍数.
I could use a regex like in this Java answer but I was hoping to find a better way (i.e. using one of kotlin's additional methods).
Once Kotlin 1.2 is released, you can use the chunked function that is added to kotlin-stdlib by the KEEP-11 proposal. Example:
val chunked = myString.chunked(2)
You can already try this with Kotlin 1.2 M2 pre-release.
Until then, you can implement the same with this code:
fun String.chunked(size: Int): List<String> {
val nChunks = length / size
return (0 until nChunks).map { substring(it * size, (it + 1) * size) }
}
println("abcdef".chunked(2)) // [ab, cd, ef]
This implementation drops the remainder that is less than size elements. You can modify it do add the remainder to the result as well.