I have a generically typed class Builder<T> that takes a constructor argument Class<T> so I can keep the type around. This is a class that I use a lot in java code so I don't want to change the signature.
When I try to use the constructor like this:
Builder<List<Number>>(List<Number>::class)
I get an error: "Only classes are allowed on the left hand side of a class literal"
有办法解决这个问题吗？
我理解整个类型擦除问题，我真的只是想让编译器满意.
Due to generic type erasure List class has a single implementation for all its generic instantiations. You can only get a class corresponding to List<*> type, and thus create only Builder<List<*>>.
该生成器实例适用于构建something个列表.同样，由于类型擦除，您可以在未经判断的强制转换的帮助下自行决定:
Builder(List::class.java) as Builder<List<Number>>
Builder(List::class.java as Class<List<Number>>)
Another approach is to create inline reified helper function:
inline fun <reified T : Any> Builder() = Builder(T::class.java)
and use it the following way:
Builder<List<Number>>()