Json 使用 jolt 将对象数组转换为数组

您可以连续使用shift和modify转换规范，例如

[
  { // form "Address" and "Hobbies" arrays
    "operation": "shift",
    "spec": {
      "users": {
        "*": {
          "name": "[#2].Name",
          "ad*": {
            "*": "[#3].ad1",//grab 1st asterisk replacement(might be multiple) after going 1 level up the tree 
            "state|zip": "[#3].ad2"
          },
          "h*": {
            "*": {
              "n*": "[#4].H&(2,1)"//grab 1st asterisk replacement after going 2 level up the tree
            }
          }
        }
      }
    }
  },
  { // concatenate the components of the "Address" array 
    "operation": "modify-overwrite-beta",
    "spec": {
      "*": {
        "ad1": "=join(', ',@(1,&))",
        "ad2": "=join(' ',@(1,&))",
        "Adress": "=concat(@(1,ad1),', ',@(1,ad2))"
      }
    }
  },
  { // get rid of extra auxiliary attributes
    "operation": "remove",
    "spec": {
      "*": {
        "ad*": ""
      }
    }
  }
]

Edit:可以直接使用concat函数，如下您在 comments 部分中提到的:

[
  { 
    "operation": "shift",
    "spec": {
      "users": {
        "*": {
          "name": "[#2].Name",
          "ad*": {
            "*": "[#3].&"
          },
          "h*": {
            "*": {
              "n*": "[#4].H&(2,1)"
            }
          }
        }
      }
    }
  },
  {
    "operation": "modify-overwrite-beta",
    "spec": {
      "*": {
        "Address": "=concat(@(1,street),', ',@(1,city),', ',@(1,state),' ',@(1,zip))"
      }
    }
  },
  {
    "operation": "remove",
    "spec": {
      "*": {
        "*t*|z*": ""
      }
    }
  }
]

但大体上，我更喜欢使用join而不是concat as much as possible作为join句柄.