Json 没有很多类的 GSON 解析

发布于05月17日

我有以下JSON，我只对获得元素"status"、"lat"和"lng"感兴趣.

使用Gson，是否可以解析这个JSON来获取这些值，而不创建代表JSON内容的整个类 struct ？

JSON:

{
  "result": {
    "geometry": {
      "location": {
        "lat": 45.80355369999999,
        "lng": 15.9363229
      }
    }
  },
  "status": "OK"
}

推荐答案

You don't need to define any new classes, you can simply use the JSON objects that come with the Gson library. Heres a simple example:

JsonParser parser = new JsonParser();
JsonObject rootObj = parser.parse(json).getAsJsonObject();
JsonObject locObj = rootObj.getAsJsonObject("result")
    .getAsJsonObject("geometry").getAsJsonObject("location");

String status = rootObj.get("status").getAsString();
String lat = locObj.get("lat").getAsString();
String lng = locObj.get("lng").getAsString();

System.out.printf("Status: %s, Latitude: %s, Longitude: %s\n", status,
        lat, lng);

Plain and simple. If you find yourself repeating the same code over and over, then you can create classes to simplify the mapping and eliminate repetition.